«Farzandlarimiz bizdan ko’ra kuchli, dono, bilimli va albatta baxtli bo’lishi shart»

aniqlovchi tenglama ( Maple da indicialeq) deb ataluvchi kvadrat tenglama hosil bo‘ladi. Berilgan differensial tenglama yechimlarining tabiati ana shu aniqlovchi tenglamaning ildizlariga bog‘liq. - tartibli differensial tenglamaning regyulyar maxsus nuqtasi atrofida ham yechim Frobenius metodi yordamida umumlashgan darajali qator ko‘rinishida izlanishi mumkin.

2.2. Oddiy differensial tenglama va uning umumiy yechimini
Maple dasturida topish
Quyida keltirilgan misollarda dsolve buyrug‘idan foydalanib birinchi tartibli yakka (skalyar) differensial tenglama yechilgan.
Ushbu birinchi tartibli chiziqli differensial tenglamani noma’lum funksiyaga nisbatan yechaylik. Dastlab tenglamani aniqlab, so‘ngra uni yechish haqida buyruq beramiz:
> deq:=diff(y(x),x)-a*y(x)=1+x;
dsolve(deq,y(x));
INCLUDEPICTURE "../../../../Farhodjon/Desktop/Documents%20and%20Settings/TV%20Markaz/Application%20Data/Microsoft/Documents%20and%20Settings/TV%20Markaz/Application%20Data/Microsoft/Norxol/Maple/images/Kitob-IV_8.gif" \* MERGEFORMAT
INCLUDEPICTURE "../../../../Farhodjon/Desktop/Documents%20and%20Settings/TV%20Markaz/Application%20Data/Microsoft/Documents%20and%20Settings/TV%20Markaz/Application%20Data/Microsoft/Norxol/Maple/images/Kitob-IV_9.gif" \* MERGEFORMAT
Bu yerda ixtiyoriy o‘zgarmas. Shunday qilib, berilgan tenglamaning yechimi
ixtiyoriy o‘zgarmas.
Yana bir differensial tenglama (Bernulli
tenglamasi)ni yechaylik (bunda berilgan tenglamani yechish haqida to‘g‘ridan-to‘g‘ri buyruq berilgan):
> dsolve(diff(y(x), x)-y(x)^2+y(x) ); # diff(y(x), x)-y(x)^2+y(x)=0 tenglamani yechish
INCLUDEPICTURE "../../../../Farhodjon/Desktop/Documents%20and%20Settings/TV%20Markaz/Application%20Data/Microsoft/Documents%20and%20Settings/TV%20Markaz/Application%20Data/Microsoft/Norxol/Maple/images/Kitob-IV_10.gif" \* MERGEFORMAT
Yana bir misol