Diskret tuzilmalardan 1-oraliq nazorat varianti №1

Diskret tuzilmalardan 1-oraliq nazorat varianti

№ 16

1. A = {1;2;3} va B = {3;4} to`plamlarning dekart ko`paytmasidan iborat to`plamning nechta elementi bor?

A) 1 B) 3 C) 4 D) 5 E) 6

2. А={1,2,3,4,5,6}. x y binary munosabat yordamida tuzilgan qism to`plamni toping
A) {(1,2), (2,5), (4,2)} B) {(1,1), (1,2), (3,6), (5,6)} C) {(2,1), (6,4)} D) {(3,7)} E) {(2,3),(5,3)}
3. A to`plamdagi R binar munosabat tranzitivlik xossasini qanoatlantiradi, agarda

A) xRx a to`plamdagi ixtiyoriy x uchun ; B) xRy dan yRx kelib chiqadi; C) xRy va yRx dan x=y kelib chiqadi; D) xRy va yRz dan xRz kelib chiqadi

4. 1 dan 20 gacha bo`lgan natural sonlar ichidan yig`indisi toq son bo`lgan 2 ta sonni nechta usulda tanlash mumkin?

A) 80 B) 90 C) 100 D) 110 E) 120

5. 12 ta predmetni 3 ta qutiga nechta ussulda joylash mumkin?

А) 91 B) 27 C) 88 D) 36 E) 120

6. Bitta ham elementga ega bo’lmagan to’plam

2. 
   cheksiz to`plam B) bo`sh to`plam C) chekli to`plam D) nol
   

7. А={1,2,3,4,5,6} to’plamdagi «o’zaro tub» binar munosabatning qism to’plami

A) {(1,1), (1,2), (3,6), (5,6)} B) {(1,2), (2,5), (4,2)} C) {1, 2, 3, 4} D) {(2,3),(5,3)}
8. Qirrasining uzunligi 1 dan 10 gacha butun son bo`lgan hechta turli to`g`ri burchakli parallelepiped qurish mumkin?

А) 220 B) 156 C) 84 D) 36 E) 1024

9.”LAZIZ” so`zini nechta usul bilan shifrlash mumkin?

A) 5! B) 4! C) 60 D) 120 E) 3!2!

10. 100 tа tаlаbа sessiya tоpshirishdi. Tаriхni 48 kishi, fаlsаfаni 42 kishi, mаtemаtikаni 37 kishi tоpshirdi. Tаriх vа fаlsаfаni 76 kishi, tаriх vа mаtemаtikаni hаm 76 kishi, fаlsаfа vа mаtemаtikаni 66 kishi tоpshirdi. Hаmmа imtihоnlаrni 5 kishi tоpshirdi. Umuman topshira olmaganlar nechta?

A) 12 B) 10 C) 3 D) 6 E) 8

_{11. 5!+6! ni hisoblang.}

A) 840 B) 84 C) 680 D) 180 E) 120

_12. Hisoblang.

A) 4 B) 6 C) 20 D) 9 E) 5

13. (a+b)¹⁰ binom yoyilmasining 2-hadi oldidagi koeffitsiyentni toping.

A) 12 B) 16 C) 6 D) 10 E) 14

_{14. Tenglamani yeching.}

A) 12 B) 10 C) 6 D) 7 E) 2