R1
R2
No worries—solving this is easier than it looks initially. The question actually has
the summary address listed in it: 192.168.144.0/20. You already know that /20 is
255.255.240.0, which means you’ve got a block size of 16 in the third octet. Starting at
144, which is also right there in the question, makes the next block size of 16 equal 160.
You can’t go above 159 in the third octet, so the IP addresses that will be forwarded are
192.168.144.1 through 192.168.159.254.
Okay, last one. In Figure 5.14, there are five networks connected to router R1. What’s
the best summary address to R2?
f I g u r e 5 .14 Summarization example 5
What is the best summary to R2?
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