Amazing properties of binomial coefficients - 2
“The official theoretical source” for this set of problems is Vinberg’s article [1]. Particularly the following theorems are considered to be known.
Wilson’s theorem. For any prime p (and for primes only) the equivalence holds (p − 1)! ≡ −1 (mod p).
Lukas’ theorem. Write the numbers n and k in base p:
d 1 0 1 0d−1 d d−1
n = n pd + n pd−1 + . . . + n p + n , k = k pd + k pd−1 + . . . + k p + k . (1)
k
Then n
≡ nd kd
nd−1 kd−1
· . . . · n1
k1
n0 (mod p) .
k
k0
Kummer’s theorem. The exponent ordp n is equal to the number of “carries” when we add k and £ = n − k in
base p.
p
Wolstenholme’s theorem. If p 5 then 2p
≡ 2 (mod p3), or, that is the same, 2p−1
k
p−1
≡ 1 (mod p3).
0
Remind that 0
= 1, n
= 0 for k > n and for k < 0 by definition.
We denote by p a prime number. For any natural n denote by (n!)p the product of all integers from 1 to n not divisible by p. If a number p is given the symbols ni, mi etc. denote the digits of numbers n, m etc. in base p.
* * *
Arithmetical triangle and divisibility
2
a) Prove that the first 3k rows of 3-arithmetical Pascal triangle contain 1(6k + 4k) residues “1” and
2
1 (6 k − 4 k) residues “2”.
Find the number of zero elements in the first 5k rows of 5-arithmetical Pascal triangle.
Find the number of non-zero elements in the first pk rows of p-arithmetical Pascal triangle.
Prove that the number of 1’s in the first m rows of 2-arithmetical Pascal triangle equals
nL−1
i=0
mi · 2
n−1 m i
k=i+1 k · 3 .
If m = 2 α1 + 2 α2 + . . . + 2 αr , where α1 > α2 > . . . > αr, then we can rewrite the last expression in the form
3α1 + 2 · 3α2 + 22 · 3α3 + . . . + 2r−1 · 3αr .
Consider n-th row of Pascal triangle modulo 2 as binary expansion of some integer Pn. Prove that
Pn = Fi1 · . . . · Fis ,
1 F = 2 + 1s i
where i , . . . , i are numbers of positions where 1’s occur in the binary expansion of n, and 2i is
i-th Fermat number.
Prove that the number of non-zero elements in n-th row of p-arithmetical Pascal triangle equals
d
(ni + 1).
i=0
a) All the binomial coefficients
n , where 0 < k < n, are divisible by p if and only if n is a power of p.
b) All the binomial coefficients
k
k
n , where 0 � k � n, are not divisible by p if and only if n + 1 is
divisible by pd, in other words, all the digits of n, except the leftmost, in base p are equal to p − 1.
Let 0 < k < n + 1. Prove that if n . p and n . p, then n+1 . p, except the case, when n + 1 is
divisible by p.
k−1 . k . k .
Generalization of Wilson’s and Lukas’ theorems
p
Prove that ord (n!) = n − (nd + . . . + n1 + n0) .
p − 1
Prove the following generalizations of Wilson’s theorem. a) (−1)[n/p](n!)p ≡ n0! (mod p);
Prove that for p 3
(pq!)p ≡ −1 (mod pq) ,
and for p = 2, q 3 (pq!)p ≡ 1 (mod pq).
pµ
0
1
d
p
n! ≡ (−1)µn !n ! . . . n ! (mod p), where µ = ord (n!)
f = ordp(
n
k
Generalized Lukas’ theorem. Let r = n − k, ). Then
(
1 n n0!
)( n1! )
( nd! )
p k
≡ (−1)
k ! r !
k ! r !
. . .
k ! r !
(mod p)
0 0 1 1 d d
a) Prove that (1 + x)pd ≡ 1 + xpd (mod p) for all x = 0, 1, . . . , p − 1.
b) Prove Laukas’ theorem algebraically.
a) Let m, n, k be nonnegative inte ger s, and (n, k) = 1. Prove that Ck
≡ 0 (mod n).
b) Prove that if n . pk
, m . p, then
mn
m
n . pk.
Let fn,a =
( k k=0
) . Prove that fn,a ≡
i=0
fni,a (mod p).
Variations on Wolstenholme’s theorem
4.1. Prove that 1 + 1 + . . . + 1 ≡ 0 (mod p2).
1 2 p − 1
Let p = 4k + 3 be a prime number. Find 1
0 2 + 1
1
+ 12 + 1
1
+ . . . + (p − 1)2 + 1
(mod p).
a) Let k be a nonnegative integer such that for any prime divisor p of the number m k is not
1 1 1
−
divisible by ( p − 1). Prove that 1k + 2 k + . . . + ( p 1)k ≡ 0 (mod m) (summation over all fractions whose
denominators are coprime to m).
b) Let k be odd and (k + 1) . (p − 1). Prove that 1 + 1 + . . . + 1 ≡ 0 (mod p2).
Prove that the equivalence (12) from Vinberg’s article holds in fact modulo p4.
Prove that the following properties are equivalent 1) 2p−1 ≡ 1 (mod p4);
1 1 1
1 p−1 1
3
2
2) +
1 2
+ . . . +
p − 1
≡ 0 (mod p ); 3)
1 12 + 22
+ . . . +
( p − 1) 2
≡ 0 (mod p ).
a) Prove algebraically that for any prime p and arbitrary k and n ( pk − k .
2. (In Vinberg’s
article this fact is proven combinatorially.
pm m
) . p
pk
k .
b) Prove the statement (9) form Vinberg’s article: for any prime p 5 and arbitrary k and n ( pm −
Let p 5. Prove that a) p2 ≡ p (mod p5); b) ps+1 ≡ ps (mod p2s+3).
m ) . p3.
p 1 p
p2
p
Prove that p3 ≡ p2 (mod p8).
Amazing properties of binomial coefficients - 3
Additional problems to previous topics
Prove that pn−1 ≡ (−1)Sk (mod p), where S
is the sum of digits of k in base p.
k
Prove that if the binomial coefficient (1), then
k
k
n is odd i.e. ki � ni for all i = 0 , 1 , . . . , d in the notations of
n d
k ≡
i=1
(−1)ki−1ni+kini−1 (mod 4).
Prove that if there are no two consecutive 1’s in the binary expansion of n then all the odd entries in n-th row ≡ 1 (mod 4), otherwise the number of entries ≡ 1 (mod 4) equals the number of entries ≡ −1 (mod 4).
Prove that the number of 5’s in each row of 8-arithmetical Pascal triangle is a power of 2. Prove the same for 1’s, 3’s and 7’s.
Prove that if we consider all the elements of the two sets
2n − 1 2n − 1 2n −
2n − 1
1
, ,
1 3 5
, . . . ,
2 n − 1
and {1, 3, 5, . . . , 2n − 1}
as a reminders modulo 2 n, then these sets coincide.
Prove that elements of a row of Pascal triangle are not coprime in the following sence. For any ε > 0
there exists N , such that for all integer n > N and k1, k2, . . . , k100 < ε√n the numbers
have a common divisor.
2n
,
n + k1
2n n + k2
, . . . ,
2n
n + k100
a) The non negative numbers m > 1, n, k are given. Prove that at least one of the numbers n
n+1 k
, . . . ,
n+k k
is not divisible by m.
n
k ,
n+1
k
b) Prove that for each k there exist infinite set of numbers n, such that all the numbers ,
k
n+k−1 are divisible by m.
k , . . . ,
Prove that for n > 1 2n+1 − 2n is divisible by 22n+2.
2n 2n−1
p−1 p−1
p−1 3
≡
Prove that for p 5 (−1) 2
p−1 4
2
(mod p ).
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