Binar daraxtni ko’rikdan o’tkazayotganda biz yuqorida har bir tugunni o’ngida va chapida turgan tugunlarni so’z bilan ifodaladik. Lekin bu usul bir muncha noqulay

O’zbekiston Respublikasi Axborot Texnologiyalari va kommunikatsiyalarini rivojlantirish vazirligi
Muhammad al-Xorazmiy nomidagi
Toshkent Axborot Texnologiyalari Universiteti
Tizimli dasturlash fanidan
Laboratoriya ish-2
Bajardi: Madaminov Dostonbek
Guruh: 311-18
Patok: SPP001-L1
Tekshirdi: Abduvaliyeva Zebiniso
Binar daraxtni vizuallashtirish

Binar daraxtni ko’rikdan o’tkazayotganda biz yuqorida har bir tugunni o’ngida va chapida turgan tugunlarni so’z bilan ifodaladik. Lekin bu usul bir muncha noqulay. Daraxtni vizual ko’rinishda ifodalash uni anglashning juda quslay usuli hisoblanadi. Daraxtni vizuallashtirishning grafik ko’rinishi va konsol oynasida ifodalash kabi turlari mavjud. Shundan konsol oynasida daraxtni vizuallashtirishni ko’rib chiqamiz. Bunda sonlar daraxt shaklida joylashtiriladi. Quyida bunday usulning dastur kodi keltirilgan.

void vizual(node *tree,int l)
{ int i;
if(tree!=NULL) {
vizual(tree->right,l+1);
for (i=1; i<=l; i++) cout<<" ";
cout<info<
vizual(tree->left,l+1);
}
}
Dastur kodi quyidagi 4.10 a-rasmdagi daraxtni konsol ekranida 4.10 b-rasm ko’rinishda ifodalaydi.



a. b.
4.10-rasm. a - binar daraxt; b - binar daraxtning ekranda namoyon bo’lishi

Yuqorida keltirilgan bir nechta algoritmlarni qo’llab bitta misol ko’rib chiqamiz.

Misol: berilgan binar daraxtning balandligini aniqlang va muvozanatlang.

Dastur kodi
#include
#include
using namespace std;
class node{
public: int info;
node *left;
node *right;
};
int k=0;
int intrave(node *tree){
if (tree!=NULL){int a=NULL, b=NULL;
if (tree->left!=NULL){ a=tree->left->info; }
if (tree->right!=NULL){ b=tree->right->info; }
cout<info<<"--chapida=>"<"<
intrave(tree->left);
intrave(tree->right); }
return 0;
}
int height(node *tree){
int h1,h2;
if (tree==NULL) return (-1);
else {
h1 = height(tree->left);
h2 = height(tree->right);
if (h1>h2) return (1 + h1);
else return (1 + h2);
}
}
int create_arr(node *tree,int *arr){
if(!tree) return 0;
else{
create_arr(tree->left,arr);
arr[k++]=tree->info;
create_arr(tree->right,arr);
}
}
node *new_tree(int *arr, int start, int end)
{
if(start>end) return NULL;
else {
int mid=(start+end)/2;
node *tree=new node;
tree->info=arr[mid];
tree->left=new_tree(arr,start,mid-1);
tree->right=new_tree(arr,mid+1,end);
return tree;
}
}
void vizual(node *tree,int l)
{ int i;
if(tree!=NULL) {
vizual(tree->right,l+1);
for (i=1; i<=l; i++) cout<<" ";
cout<info<
vizual(tree->left,l+1);
}
}
int main()
{ int n,key,s; node *tree=NULL,*next=NULL;
cout<<"n="; cin>>n; int arr[n];
for(int i=0; i
node *p=new node;
node *last=new node;
cin>>s;
p->info=s;
p->left=NULL;
p->right=NULL;
if(i==0){tree=p; next=tree; continue; }
next=tree;
while(1)
{ last=next;
if(p->infoinfo)next=next->left;
else next=next->right;
if(next==NULL)break; }
if(p->infoinfo)last->left=p;
else last->right=p;}
cout<
intrave(tree);
cout<<"\nya'ni\n";
vizual(tree,0);
int h=height(tree);
cout<<"balandligi="<
create_arr(tree,arr);
for(int i=0;i
tree=new_tree(arr,0,k-1);
vizual(tree,0);
getch();
}
Dastur natijasi