B “Tasdiqlayman” o’quv ishlari bo’yicha direktor movini

IV. Mustaqil ish: (10 daqiqa)
Deyteriy ₁²H yadrosining bog`lanish energiyasini toping . <sub>1</sub><sup>2</sup>H izotopining
massasi M = 2,014102 m.a.b , proton va elektronlarning massalari
m<sub>p</sub> = 1,007276 m.a.b , m<sub>n</sub> = 1,008665 m.a.b va m<sub>e</sub> = 0,000549 m.a.b .
B – n .
M = 2,014102 m.a.b E<sub>bog`</sub> = mC² m = m_p + m_n –M +m_e
m_p = 1,007276 m.a.b
m_n = 1,008665 m.a.b E_{bog`</sub> = (m<sub>p</sub> + m<sub>n</sub> – M +m<sub>e</sub>) = 931,5 MeV =
m<sub>e</sub> = 0,000549 m.a.b
 = 2,224 MeV
E<sub>bog`} - ?
Alyuminiy ₁₃²⁷ Al yadrosining bog`lanish energiyasini toping .<sub>13</sub><sup>27</sup>Al atomining
massasi M = 26,981539 m.a.b proton , neytron va elektronlarning massalari :
m<sub>p</sub> = 1,007276 m.a.b , m<sub>n</sub>= 1,008665 va m<sub>e</sub> = 0,000549 m.a.b .
B – n .
M = 26,981539 m.a.b Ye: E<sub>bog`</sub> = ( Zm_p+ Nm_n –M + Zm_e) ^.931,5 MeV =
m_p = 1,007276 m.a.b
m_n= 1,008665 m.a.b = 224,9 Mev .
m_e = 0,000549 m.a.b
Z = 13 N =14

E<sub>bog`</sub> -?
Xeyger sanagichining elektr sig`imi C = 25 pf . Unga ulangan voltmeter kuchlanishining U = 20 v pasayganligini ko`rsatadi .Ana shu sanagichda necha juft ion hosil bo`lgan ? e = 1,6 10^-19 kl
B – n . q
C= 25 ^. 10^-12 F C =  (1) q = N ^.e (2) (2)ni (1)ga qo`yib N ni topsak
U = 20v U
e = 1,6 <sup>.</sup>10<sup>-19 kl</sup> CU 25 <sup>.</sup>10<sup>-12 .</sup>20
<sup></sup> N =  =  = 3,1 <sup>.</sup> 10<sup>9</sup>
N - ? e 1,6 <sup>.</sup>10<sup>-19</sup>
V. Yangi mavzuni mustahkamlash:
Serpuxovodagi yuqori energiyalar fizikasi institutidagi tezlatgichda protonlar W = 76GeV energiyaga olsa , ularning massasi necha marta ortadi ? Protonning tezlikdagi energiyasi E<sub>0</sub> = 938 MeV .
B – n . Ye: Massasi va energiyaning o`zaro bog`lanish qonuniga muvofiq E= ms<sup>2</sup>
W = 76 GeV m E
E<sub>0</sub> = 938 MeV E<sub>0</sub> = m<sub>0</sub>s<sup>2</sup> (1)  =  (2) E = W +E<sub>0</sub> to`la energiyani
 m₀ E₀ (2 ) ga qo`ysak .
m m W+E<sub>0</sub> 76 <sup>.</sup>10<sup>9</sup>eV + 938 <sup>.</sup>10<sup>6</sup>eV
 - ?  =  =  = 82 .
m<sub>0</sub> m<sub>0</sub> E<sub>0</sub> 938 <sup>.</sup> 10<sup>6</sup>eV
Protonning massasi uning tinchlikdagi massasiga nisbaran n= 4 marta ortishi uchun proton qanday tezlik bilan harakatlanishi kerak ? m<sub>0</sub>
B – n . Ye : Jism massasining tezlikka bog`lanishini ifodalovchi m =  formulaga
n = 4
 
v - ? c²
v² m₀ 1 C
ko`ra 1 -  = (  ) =  =  =  ^. S = 0,968 S
C² m n² n 4
VI. Xulosa: 5 daqiqa.

O’qituvchi o’quvchilarning javobidan so’ng, o’z yutuqlarini va kamchiliklarini ko’radi, o’ziga xulosa chiqaradi. O’quvchilarni rag’batlantirib baholaydi.
VII. Uyga vazifa:2 daqiqa

Yerevan fizika institutidagi tezlatkichda energiyasi W = 6GeV bo`lgan elektronlar olish mumkin . Bunday elektronlarning massasi qanday va ularning massasi tinchlikdagi massasidan necha marta katta ? Elektronning tinchlikdagi energiyasi E₀ = 0,511 MeV massasi esa m₀ = 9,11 _{* 10}^-31 kg .

B – n
1. A.G. G’aniyev “Fizika I qism ” akademik litsiy va kollejlar uchun darslik. T-2003 y
2. S.N. Shaxmayev “Fizika 10 sinf ” darslik T-2003 y
3. N.S.Turdiyev “Fizika 7 sinf” darslik T- 2005 y
4. R.N.Remkeyvich “Masalalar yechish” darsligi T-3 y