ATESTATSIYA SAVOLLARI (2021)
1. Tengsizlikning eng kichik natural yechimini toping.
|𝑥
2
− 3𝑥 + 2| − 𝑥
2
+ 2𝑥 − 1
|𝑥| − |𝑥 − 1|
≤ 0
2. Teng yonli trapetsiya diagonali 10 ga teng. Asos tekisligi bilan hosil qilgan burchagi kosinusi
√2
10
ga teng
bo’lsa, trapetsiya yuzini toping.
3.
𝑥, 𝑦, 𝑧 ketma-ket sonlar bo’lsa,
𝑥
𝑦
+
𝑦
𝑧
+
𝑧
𝑥
+
𝑦
𝑥
+
𝑥
𝑧
+
𝑧
𝑦
ni hisoblang.
4. Hisoblang:
((
1
7
)
√3−√5
)
√5+√3
5. Soddalashtiring:
cos
2
(𝑥 + 𝑦) − cos
2
(𝑥 − 𝑦)