3. .
4. 0, 1, 2, 3, 4, 5, 6, - k
N= n1*n2*n3*n4
n1=6 n2=7 n3=7 n4=1
N=6*7*7*1=294
5. (xvy&⌐zv⌐x&⌐y&z)&x&⌐y
x
|
y
|
z
|
⌐z
|
y&(⌐z)
|
xv(y&(⌐z))
|
⌐x
|
⌐y
|
(⌐x)&(⌐y)
|
((⌐x)&(⌐y))&z
|
(xv(y&(⌐z)))v(((⌐x)&(⌐y))&z)
|
((xv(y&(⌐z)))v(((⌐x)&(⌐y))&z))&x
|
(((xv(y&(⌐z)))v(((⌐x)&(⌐y))&z))&x)&(⌐y)
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
Dizʻyunkatsiya amali :
x
|
y
|
x v y
|
0
|
0
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
Konʻyunksiya amali:
x
|
y
|
x & y
|
0
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
Inkor qilish amali:
Do'stlaringiz bilan baham: |