18 solution q. E. D



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Bog'liq
Chapter 18

v
G
V
IC
G
V
r
G
/IC
v
G


913
© 2016 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently 
exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from the publisher. 
18–2.
M
O
0.5 m
The wheel is made from a 5-kg thin ring and two 2-kg
slender rods. If the torsional spring attached to the wheel’s
center has a stiffness , and the wheel is
rotated until the torque 
is developed,
determine the maximum angular velocity of the wheel if it
is released from rest.
M
=
25 N
#
m
k
=
2 N
#
m
>
rad
SOLUTION
Kinetic Energy and Work: The mass moment of inertia of the wheel about point is
Thus, the kinetic energy of the wheel is
Since the wheel is released from rest,
. The torque developed is 
.
Here, the angle of rotation needed to develop a torque of 
is
The wheel achieves its maximum angular velocity when the spacing is unwound that
is when the wheel has rotated 
. Thus, the work done by 
is
Principle of Work and Energy:
Ans.
v
=
14.0 rad/s
0
+
156.25
=
0.79167 
v
2
T
1
+ ©
u
1
-
2
=
T
2
=
u
2

0
12.5 rad
=
156.25 J
U
M
=
L
Md
u
=
L
12.5 rad
0
2
u
d
u
q
M
u
=
12.5 rad
u
=
12.5 rad
2
u
=
25
M
=
25 N
#
m
M
=
k
u
=
2
u
T
1
=
0
T
=
1
2
I
O
v
2
=
1
2
(1.5833) 
v
2
=
0.79167 
v
2
=
1.5833 kg
#
m
2
=
5(0.5
2
)
+
2
c
1
12
(2)(1
2
)
d
I
O
=
m
R
r
2
+
2
¢
1
12
m
r
l
2


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