11-sinf matematika II variant sharning hajmi qaysi formula bilan hisoblanadi

11-sinf MATEMATIKA II VARIANT

1. 
   Sharning hajmi qaysi formula bilan hisoblanadi:
   

1. 
   V=R²H /3 B) V=4R³ /3 D) V=3R³ /4
   

2. 
   Y=2x^1/2, y=6,x=0 chiziqlar bilan chegaralangan shakl yuzini toping:
   

1. 
   18 B) 17 D) 20
   

3. f(x)=6x(x-2) funksiyaning F(x) boshlang’ich funksiyasini toping:
A) F(x)=2x³-6x²+9 ; B) F(x)=3x³-6x²+7 D) F(x)=2x³+6x²+9
4. Integralni hisoblang: ^x 2^x dx
A)F(x)=12^x/ln12+c B) F(x)=12^xln12+c D) F(x)=6^xln6 +c
5. Aniq integralni hisoblang:
A)17 B) 28 D) 18
6. Kiitob javonida matematikadan 9 ta chet tilidan 4 ta va ona tilidan 6 ta kitob turibdi.Javondan bitta kitobni necha usulda tanlash mumkin.
A)20 B) 19 D)216
7. Qizil,qora. Ko’k va yashil sharlarni bir qatorga necha usulda joylashtirish mumkin
A) 10 B) 9 D)24
8. 5 ta kitobdan 3 ta kitobni necha usulda tanlashimiz mumkin
A) 2 B) 10 D) 8
9. Malumotlar qatorlari 3,4,4,5,6,6,7,7,7,8,8,9,10 berilgan , ularning o’rta qiymatini toping

1. 
   5.1 B) 6.5 D) 5.7
   

10. . Malumotlar qatorlari 3,4,4,5,6,6,7,7,7,8,8,9,15 berilgan , ularning medianasiini toping
A) 7 B) 6 D) 8
11. Bitta yog’i ko’pburchak, qolgan uoqlari esa umumiy uchga ega uchburchakdan iborat ko’pyoq nima deb ataladi?
12. Uchburchakli piramidaning hajmini topish formulasini yozing.
13.Sharni bo’yash uchun 100 gramm bo’yoq ishlatildi.Agar sharning diametric 3 marta orttirilsa, uni bo’yash uchun necha gramm bo’yoq kerak bo’ladi.
14.To’rtburchakli muntazam piramidaning balandligi 24 ga, asosining tomoni esa 14 ga teng. Uning apofemasini toping.
15. Kesik konus yon sirtining yuzini toppish formulasini yozing.

II variant JAVOBLAR

1. 
   B
   
2. 
   A
   
3. 
   A
   
4. 
   A
   
5. 
   D
   
6. 
   B
   
7. 
   D
   
8. 
   B
   
9. 
   D
   
10. 
    A
    
11. 
    6
    
12. 
    V=S_asosH/3
    
13. 
    900 gramm
    
14. 
    25
    
15. 
    S_yon= l (r₁+r₂)