1. Simpleks usulining mazmun-mohiyati; Simpleks jadvalini tuzish

Iteratsiya 2 4.10-jadval
1 2 3 4 5 6 7 8 9
i Bazis Сb P0
2 3 0 0 0
P1 P2 P3 P4 P5
1 P3 0
2 P1 2 7/3 1 0 0 7/3 -1/3
3 P2 0
4 0
4.10-jadvaldagi bo„sh kataklarni 3.4-rasmda ko„rsatilgan tartibda to„ldiramiz.
Uning natijasi quyidagicha bo„ladi
Iteratsiya 3 4.11 -jadval
1 2 3 4 5 6 7 8 9
I Bazis Сb P0
2 3 0 0 0
P1 P2 P3 P4 P5 1 P3 0 4-(10/7)*(7/3)=2/3 0 0 1 0-(10/7)*7/3=- 10/3 -1/7-(10/7)*(- 1/3)=1/3 2 P1 2 7/3 1 0 0 7/3 -1/3 3 P2 3 4-(4/7)*(7/3)=8/3 0 1 0 0-(4/7)*(7/4)=- 4/3 1/7-(4/7)*(- 1/3)=1/3 4 12-(- 2/7)*7/3=38/3 0 0 0 0-(- 2/7)*(7/3)=2/3 3/7-(-2/7)*(- 1/3)=1/3
4.11 -jadvalning natijaviy ko„rinishi quyidagicha
Iteratsiya 3 4.12-jadval
1 2 3 4 5 6 7 8 9
I Bazis Сb P0
2 3 0 0 0
P1 P2 P3 P4 P5 1 P3 0 2/3 0 0 1 -10/3 1/3 2 P1 2 7/3 1 0 0 7/3 -1/3 3 P2 3 8/3 0 1 0 -4/3 1/3 4 38/3 0 0 0 2/3 1/3